(6x)^2-136=2x^2

Solution for (6x)^2-136=2x^2 equation:

(6x)^2-136=2x^2

We move all terms to the left:

(6x)^2-136-(2x^2)=0

We add all the numbers together, and all the variables

4x^2-136=0

a = 4; b = 0; c = -136;
Δ = b2-4ac
Δ = 02-4·4·(-136)
Δ = 2176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2176}=\sqrt{64*34}=\sqrt{64}*\sqrt{34}=8\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{34}}{2*4}=\frac{0-8\sqrt{34}}{8}
=-\frac{8\sqrt{34}}{8}
=-\sqrt{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{34}}{2*4}=\frac{0+8\sqrt{34}}{8}
=\frac{8\sqrt{34}}{8}
=\sqrt{34}
$